Agarden area is 30 ft long and 20 ft wide. a path of uniform width is set inside the edge. if the remaining garden is 400ft^2, what is the width of the path?

2.19 ft ( approx )

Step-by-step explanation:

Let x be the width ( in ft ) of the path,

Given,

The dimension of the garden area,

Length = 30 ft, width = 20 ft,

So, the dimension of the remaining garden ( garden excluded path ),

Length = (30 - 2x) ft, width = (20-2x) ft

Thus, the area of the remaining garden,

A=(30 - 2x)(20 - 2x)

According to the question,

A = 400 ft²,

By the quadratic formula,

⇒ x ≈ 22.8  or x ≈ 2.19,

∵ Width of the path can not exceed 30 ft or 20 ft

Hence, the width of the path is approximately 2.19 ft.

part a

in a city ice cream is mostly only bought when the temperature is very high as ice cream cools down our

so we can derive the conclusion that as the temperature increases the number of ice creams sold also increases

part b

y intercept is 5

slope is 2

happy to

pls mark as brainliest

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.