5stacks of coins that looks identical. each stack has 5 coins each. 4 of those stacks weigh the same, 1 stack has coins that weigh exactly 1 pound less. using a digital scale once, find out the position of the stack that is less weight.

Step-by-step explanation:

The digital scale has to be used once.

Let the coins that have normal weights are normal coins and the coins that has a weight 1 pound less are called defected coins.

5 stacks are there in which any four contains normal coins and 1 stack contains defected coins.

Took 1 coin from 1st stack, 2 coins from 2nd stack and so on..

Weigh the coins and see the result.

If the total weight is 1 pound less than the stack 1 contains defected coin.

If the total weight is 2 pounds less than the stack 2 contains defected coin.

If the total weight is 3 pounds less than the stack 3 contains defected coin.

If the total weight is 4 pounds less than the stack 4 contains defected coin.

If the total weight is 5 pounds less than the stack 5 contains defected coin.

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

idk

step-by-step explanation: