Percival plans to flip a coin times and record the results of each flip. what is the probability that the coin lands with the heads side up the first times and the tails side up the last times?

P(heads on first time ) =  

P(tails on last flip) =  

Step-by-step explanation:

when Percival flips coin several times and record the result.

so every time he tosses coin there is probability of getting heads or tails is

P(heads) =  

and for tails

P(tails) =  

so, probability of getting heads while tossing coin first time is  equal to

               P(heads on first time ) =  

again, probability of getting tails while tossing coin for last time is  equal to

               P(tails on last flip) =  

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."