In a random sample of 300 women, 49% favored stricter gun control legislation. in a random sample of 200 men, 28% favored stricter gun control legislation. construct a 98% confidence interval for the difference between the population proportions p1 - p2

Construct a 98% confidence interval for the difference between the population proportions p1 - p2 is ( 0.110199 and 0.309801)

Step-by-step explanation:

Given data

sample n1 = 300 women

sample n2 =  200 men

control legislation f1 = 49% = 0.49

control legislation f2 = 28% = 0.28

to find out

Construct a 98% confidence interval for the difference between the population proportions p1 - p2

solution

we know difference of control legislation = f1 -f2

so difference is 0.49-0.28 = 0.21

so for 98% confidence  Z value is 2.326 from standard table

and interval for difference formula is

f1 - f2 - Z

and

f1 - f2 + Z

put all these value and we get difference of population proportion are

0.49 - 0.28 - 2.326

and

0.49 - 0.28 + 2.326

= 0.110199

and

= 0.309801

Construct a 98% confidence interval for the difference between the population proportions p1 - p2 is ( 0.110199 and 0.309801)

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

this is false ^.^ lol