Astudy claims that college students spend an average of 4 hours or less studying per day. a researcher wants to check if this claim is true. a random sample of 121 college students randomly selected and it showed that average of hours studying per day was 3.15 with a standard deviation of 1.2 hours. using the 10% significance level, can you conclude that the claim college students spend an average of 4 hours or less studying per day is valid?
1. h0 hypothesis: a. μ > 4 b. μ ≥ 4 c.μ ≤ 4 d. μ < 4
2. critical value: a. -1.28 b. 1.28 c. 1.645 d. -1.645
3. test statistics: a. -5.89 b. 5.89 c. -7.79 d. 7.79
4. comment: a: accept that college students spend an average of 4 hours or less studying per day
b: reject that college students spend an average of 4 hours or less studying per day

n = 121

x = 3.15

Since we are given that the claim  is college students spend an average of 4 hours or less studying per day is valid

Null hypothesis :

Alternate hypothesis:

1)  

Now we are given that significance level is 10%

So, confidence interval is 90%

Critical value at 90% is 1.645

2)Critical value : B : 1.645

Since n >30

So we will use z test

Now we are supped to calculate z statistics

Formula :

3)So,  Test statistics:  C. -7.79

Since the z value falls in the critical region

So, we reject the null hypothesis

So,  that college students spend an average of 4 hours or less studying per day

4) A: Accept that college students spend an average of 4 hours or less studying per day

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s