A4.00 m long pole stands vertically in a lake having a depth of 2.50 m. the sun is 40.0° above the horizontal. determine the length of the pole's shadow on the bottom of the lake. take the index of refraction for water to be 1.33.

The shadow of the pole is; 3.617 m

From the diagram, we can say with the aid of trigonometric ratios that;

tan 50 = b/1.5

Thus; b = 1.5 * tan 50

b = 1.787 m

From snell's law, we can say that;

sin 50/sin θ = 1.33

Thus;

sin θ = (sin 50)/1.33

sin θ = 0.575973

θ = 35.1678°

Similarly;
tan θ = a/2.5

a = 2.5 * tan 35.1678°

a = 1.83

Shadow of pole = a + b

Shadow of pole = 1.83 + 1.787 = 3.617 m

Read more about Trigonometric ratios at; link

3.541 m

Step-by-step explanation:

 From Diagram we can say that

b=1.787 m

also we know

a=1.754

thus shadow of pole

step-by-step explanation:

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