Aball is thrown from a height of 205 feet with an initial downward velocity of 11 ft/s. the ball's height h (in feet) after t seconds is given by the following.
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The ball hits the ground at approximately 3.25 seconds.

Step-by-step explanation:

It hits the ground when the distance between the ball and the ground is 0.  In other words, when h is 0.

We need to solve the following equation:

Compare this to and you should determine the values for .

.

Plug these values into the quadratic formula:

Let's type both into a calculator:

So the ball hits the ground at approximately 3.25 seconds.

answer: i feel you honey.

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0