Amodel rocket is launched with an initial upward velocity of 54 m/s. the rocket's height h (in meters) after t seconds is given by the following.

Step-by-step explanation:

Let's first put that polynomial in standard form by descending powers of t:

If we are looking for the times where the rocket is at a height of 26 m, we sub in a 26 for h(t) and factor to solve for t.  First we get all the terms on one side of the equals sign and set it equal to zero.

That is a second degree polynomial so you can factor it however you are most comfortable to get the values of t are:

t = .51 sec and t = 10.29 sec

Since this is a polynomial, there will be 2 values of t for this time with y being the height and x being the time.  The parabola is symmetrical about the vertex so there are 2 values of t (or x) that equal height (or y).

solve systems of equations by graphing. a system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. the solution of such a system is the ordered pair that is a solution to both equations. to solve a system of linear equations graphically we graph both equations in the same coordinate system