Perform the indicated operation. x^2-y^2/3x*3y/x+y

x^2 - y^3 + y

Step-by-step explanation:

Simplify the following:

x^2 - (3 y^2 x y)/(3 x) + y

-(y^2 x×3 y)/(3 x) = 3/3×(-y^2 x y)/x = (-y^2 x y)/x:

x^2 + -(y^2 x y)/x + y

(-y^2 x y)/x = x/x×-y^2 y = -y^2 y:

x^2 + -y^2 y + y

-y^2 y = -y^(2 + 1):

x^2 + -y^(2 + 1) + y

2 + 1 = 3:

 x^2 - y^3 + y

168

step-by-step explanation:

i am pretty sure that the answer is 168

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)