The heights of a certain type of tree are approximately normally distributed with a mean height = 5 ft and a standard deviation = 0.4 ft. which statement must be true?

Answer: f(x) = -2x^3 +3x^2 +11x -6see attachedan infinite number. since the magnitude of the leading coefficient is not specified, it may be any negative number. (we have chosen the smallest magnitude integer that makes all coefficients be integers.)step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

It was 9: 5 it would the vote receive the vote

Alex need : 1: using your compass, draw a circle and label the center  o.2:   using your straightedge, draw a diameter of the circle, labeling the endpoints  aand  b.3:   construct the perpendicular bisector of the diameter,  .4:   label the points where the bisector intersects the circle as  c  and  d.5:   connect points  a  to  b  to  c  to  d  to form the square.britannie need : 1: use the given center and the straightedge to construct a radius of the circle. use the compass to measure the radius.2: using this radius, place the point of the compass at the endpoint of the radius on the circle and make an arc that intersects the circle.3: keeping the same radius, place the point of the compass at the point of intersection of the arc (from step 2) and make another arc that intersects the circle.  4: continue making consecutive arcs around the circle as described in step 3 until the circle has been divided into six 60º arcs.5: construct the sides of the equilateral triangle by connecting the endpoints of three consecutive 120° arcs.