Abird experiences an acceleration of -1.80 m/s2 for 3.81 s, and ends up 26.5 m to the left of its starting point. what is its final velocity?

-10.4 m/s

Step-by-step explanation:

Given:

x = -26.5 m

x₀ = 0 m

a = -1.80 m/s²

t = 3.81 s

Constant acceleration equation:

x = x₀ + v₀ t + ½ at²

-26.5 = 0 + v₀ (3.81) + ½ (-1.80) (3.81)²

v₀ = -3.53

The initial velocity was -3.53 m/s.  So the final velocity is:

v = at + v₀

v = (-1.80) (3.81) + (-3.53)

v = -10.4 m/s

-10.4 m/s

Step-by-step explanation:

A bird experiences an acceleration of -1.80 m/s2 for 3.81 s, and ends up 26.5 m to the left of its starting point. Therefore, its final velocity is -10.4 m/s.

v = (-1.80) (3.81) + (-3.53)

b) well because you get well

answer: 177/8

step-by-step explanation: