Compute the permutations and combinations.
from a committee consisting of 5 men and 6 women, a sub-committee is formed consisting of 4 men and 3 women. how many different subcommittees are possible?
100
360
600

100

From 5 men you can form 5x4x3x2 /(4!) different committes of 4 men = 5 different committes.

From 6 women, you can form 6x5x4 / (3!) different committes of 3 women = 20 different committes.

Total combinations: 5 x 20 = 100.

Number nine is f(x)= 40x : ) hoped i ya