There are 7 performers who will present their comedy acts this weekend at a comedy club. one of the performers insists on being the last stand-up comic of the evening. if this performer's request is granted, how many different ways are there to schedule the appearances?

720

Step-by-step explanation:

Given : Number of performers who will present their comedy acts  = 7

If one of the performers insists on being the last stand-up comic of the evening and performer's request is granted, then its position got fixed.

Now, the remaining performers = 6

Now , the number of different ways to schedule the appearances is given by :-

Hence, the number of different ways to schedule the appearances =720

65

step-by-step explanation:

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: