Identify the vertical and horizontal asymptotes for (2x+4)/(x^2+5x+6)
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Step-by-step explanation:

(2·x + 4) / (x^2 + 5·x + 6)

factorise

= 2·(x + 2) / ((x + 3)·(x + 2))

= 2 / (x + 3)

vertikal asymptotes x = -3

horizontal asymptotes y = 0

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

your answer is a

step-by-step explanation:

4*4*4*4=256