Atest score of 48.4 on a test having a mean of 66 and a standard deviation of 11. find the z-score corresponding to the given value and use the z-score to determine whether the value is significant. consider a score to be significant if its z-score is less than minus2.00 or greater than 2.00. round the z-score to the nearest tenth if necessary.

The z-score is -1.6 and it is not significant .

Step-by-step explanation:

Given : Test score = 48.4

            Mean = 66

            Standard deviation = 11

To Find :Find the z-score corresponding to the given value and use the z-score to determine whether the value is significant.

Solution:

Formula :

Substitute the values

So, the z-score is -1.6

Now we are given that Consider a score to be significant if its z-score is less than -2.00 or greater than 2.00.

Since -1.6>-2 and -1.6<2

So, It is not significant

Hence the z-score is -1.6 and it is not significant .

answer: a

step-by-step explanation: the answer is a due to the rule of symmetry; that a line of symmetry must divide a figure into 2 pieces that are the exact same, only reflected over a line of symmetry. b and c do not have lines of symmetry and would not divide the figure evenly, thus making the answer a.

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.