Which is the graph of f(x) = (x + 3)(x - 2)?

Attached picture is the graph you need

Step-by-step explanation:

This is a quadratic equation, this is determined by doing the following: (x+3)*(x-2)=x2+x-6, the term x2 is the proof that this is a quadratic equation.

Its roots are located in x=-3 and x=2,

Meaning that the graph has the following points (-3,0) and (2,0), among others.

Step-by-step explanation:

Sounds as tho' there were several answer choices.  Always share possible answer choices if they're mentioned in the problem.

If we set (x + 3)(x - 2) = 0 and solve for x, we get x = -3 and x = 2.  These are the x-intercepts.  

The vertex of this parabolic function is exactly halfway between -3 and 2, that is, at x = (-3+2)/2, or -3/2.

We need only calculate y for x = -3/2 to finish finding the vertex:

f(-3/2) = (-3/2 + 3)(-3/2 - 2) = (3/2)(-7/2), or y = -21/4.

The vertex of this graph is at (-3/2, -21/4).  

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step-by-step explanation:

the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9