Consider the following hypotheses: h0: mean = 5 h1: mean < 5 a test is performed with a sample of size 25. the sample mean was 4.73 and the population standard deviation is 1.2. assume that the population is approximately normal. use the ti-84 plus calculator to compute the p-value. round your answer to four decimal places (for example: 0.0138). write only a number as your answer.

0.1406.

Step-by-step explanation:

Given :

To Find : compute the P-value.

Solution:

Sample size = 25

n < 30

So, we will go for t-test

Now we are given that  the population standard deviation is 1.2.

Where s is the variance

So, the variance is 36

we require sample standard deviation for t test

So, Sample standard deviation =

                                                  =

                                                  =

Formula of t-test =

Where s is the standard deviation of sample

Sample mean = 4.73

Mean =

s = 1.2247

n =25

So,  

So, p value with respect to t-table is 0.1406.

Hence p-value is  0.1406.

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you