Prove that for all scalars: a, b k = that: sigma^n_k = 1 a_k b_k lessthanorequalto [sigma^n_k = 1 a^2_k]^1/2 [sigma^n_k = 1 b^2_k]^1/2 a. prove the parallelogram law: ||u + v||^2 + ||u - v||^2 = 2||u||^2 + 2||v||^2 b. explain why it is called the parallelogram law. prove: = 1/4 ||u + v||^2 - 1/4 ||u - v||^2 write the formula for the euclidean norm in e. show that 1/||v|| v is a unit vector. use the properties of a norm to show that the metric: d(u, v) = ||u - v||

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

i think the answer is b

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !