Mathematics, 30.07.2019 20:30, Nov25
2. suppose a is invertible. a. (25 points) explain why aa is also invertible. b. (25 points) then show that a'=(a^t a^-1) a^t
Answers: 2
![\Rightarrow A'=(A^{T} \times A^{-1})\times A^{T}\\\\\Rightarrow \text{Cancelling A' from both sides}\\\\\Rightarrow I=(A^{-1})\times A^{T}\\\\\Rightarrow A^{-1}= [A^{T}]^{-1}\\\\\Rightarrow \frac{Adj.A}{|A|}=\frac{Adj.[A^{T}]}{|A^{T}|}\\\\As, |A|=[|A|]^{T}\\\\Adj.A=Adj.[A^{T}]\\\\A=A^{T}](/tpl/images/0151/7667/63c0c.png)
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2. suppose a is invertible. a. (25 points) explain why aa is also invertible. b. (25 points) then sh...
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