Mathematics

Mathematics, 30.07.2019 20:20, Greekfreak

(a) find the remainder when 15! is divided by 17. (b) find the remainder when 2(26! ) is divided by 29, thatermine whether 17 is a prime by deciding whether 16! = -1

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Mathematics, 27.07.2019 18:00, anna40794

When the polynomial p(x) is evaluated at x = 9, the result is 6. which statement must be correct? a) if p(x) is divided by x – 9, the remainder is 6. b) if p(x) is divided by x – 6, the remainder is 9. c) if p(x) is divided by x + 6, the remainder is 9. d) if p(x) is divided by x + 9, the remainder is 6.

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31.) it is given that f(x) = ax^(3) + bx² -3, where a and b are constants.(a) when f(x) is divided by x - 1, the remainder is 0; when it is divided byx+1, the remainder is -2. find the values of a and b.(s3/q21(b) find the remainder when f(x - 1) is divided by x - 1.{i have found (a),the value of a and b ,which is a=1 b=2 with (b)

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Computers and Technology, 17.09.2019 17:30, hanz73

Define a function is_prime that receives an integer argument and returns true if the argument is a prime number and otherwise returns false. (an integer is prime if it is greater than 1 and cannot be divided evenly [with no remainder] other than by itself and one. for example, 15 is not prime because it can be divided by 3 or 5 with no remainder. 13 is prime because only 1 and 13 divide it with no remainder.) this function may be written with a for loop, a while loop or using recursion.

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Mathematics, 24.09.2019 02:30, anayabeatriz

Ch – 2 polynomials q1. write (i) a binomial of degree 100 (ii) a monomial of degree 23 q2. write the coefficient of i) x3 in 2x + x2 – 5x3 + x4 ii) x2 in (π/3) x2 + 7x – 3 iii) x in √3 - 2√2x + 4x2 q3. if p(y) = 4 + 3y – y2 + 5y3, find (i) p(0) ii) p(2) iii) p(-1) q4. find the zero of the polynomial i) h(x) = 6x-1 ii) p(t) = 2t-3 q5. find the remainder in each case if p(x) is divided by g(x): (i) p(x) = x3 – 6x2 + 2x – 4, g(x) = 1 – 2x; (ii) p(x) = 2x3 – 5x2 + 4x – 3, g(x) = 3x + 1. q6. in each of the following, find the value of k such that g(x) a factor of p(x): (i) p(x) = 2x3 + kx2 + 11x + k + 3, g(x) = 2x – 1; (ii) p(x) = 25x4 + 10x3 – 5kx2 + 15kx – 1, g(x) = 2 + 5x. q7 . find the value of k if p(x) = 3x3 – 2kx2 + 5x – 4 and q(x) = 2x3 – kx2 – 5k leave the same remainder when divided by x + 1.

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