Mathematics, 29.07.2019 21:10, emilyplays474

Use the formula ln(1 + x) = ∞ n = 1 (−1)n − 1xn n = x − x2 2 + x3 3 − x4 4 + for |x| < 1 and your knowledge of alternating series to find the smallest n such that the partial sum sn approximates ln 3 2 to within an error of at most 10−3. confirm this using a calculator to compute both sn and ln 3 2 . (round your answers to six decimal places.)

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Use the formula ln(1 + x) = ∞ n = 1 (−1)n − 1xn n = x − x2 2 + x3 3 − x4 4 + for |x| < 1 and you...