Pasha works as a food scientist. he designed a recipe for crackers that are 60% wheat flour by weight. he made a test batch of the crackers from 1 1/4 total pounds of ingredients. what weight of wheat flour did pasha use in the test batch?

the weight of wheat flour  Pasha used in the test batch is 3/4 pounds

Step-by-step explanation:

According to the given statement:

Pasha designed a recipe for crackers that are 60% wheat flour by weight

60% = 60/100 = 0.6 = 6/10

He made a test batch of the crackers from 1 1/4 total pounds of ingredients.

First of all change the whole fraction which is 1 1/4 into improper fraction.

1 1/4 = 5/4

Now multiply 6/10 with 5/4 to get the weight of wheat flour Pasha used in the test batch.

= 6/10 * 5/4

6 and 4 will be cancelled out by table of 2.

= 3/10 * 5/2

Now we can cancel out 5 and 10 by the table of 5.

3/2 * 1/2

Now multiply both the terms:

3/4 pounds

Thus the weight of wheat flour  Pasha used in the test batch is 3/4 pounds

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

answer:

a=9

step-by-step explanation: lmk if you need a explanation