Which trigonometric ratios are correct for triangle
abc? select three options.
sin(c) = 3
cos(b) = ?
tan(c) = 3
sin(b) = 1
tan(b) = 23

none

step-by-step explanation:

the 30 60 90 triangle has sides in the ratio of 1 : sqrt{3} : 2 so remaining leg 9sqrt{3}.

sin c = sqrt{3}/2

cos b = sqrt{3}/2

tan c = sqrt{3}

sin b = 1/2

tan b = 1/sqrt{3}

table 3 represents a direct variation function. : )

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)