Mathematics
Mathematics, 27.07.2019 05:10, dv2200342

Decide whether the stationary point (0,0,0) is asymptotically stable. = - +y+52 =-2 - y =-2y +2 = 2 - y . - 2y. =-3z = +y - 2 = ਙ +3y - 2

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Decide whether the stationary point (0,0,0) is asymptotically stable. = - +y+52 =-2 - y =-2y +2 = 2...

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