A: what are the solutions to the quadratic equation x^2+9=0?
b: what is the factored form of the quadratic expression x^2+9?
select one answer for question a, and select one answer for question b.
a: x=3
a: x=-3i
a: x=3i or x=-3i
a: x=3 or x=-3
b: (x+3)(x+3)
b: (x-3i)(x-3i)
b: (x+3i)(x-3i)
b: (x+3)(x-3)

Part A)

x=-3i

x=3i

Part B)

(x+3i)(x-3i)

Step-by-step explanation:

Given:

Part A)

x^2+9=0

x^2=-9

x= √-9

x=√-1 *√9

x=± i *3

x=±3i

Part B)

x^2+9=0

x^2 - (-9)=0

x2-(3i)^2=0

(x-3i)(x+3i)=0 !

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.