Asoccer ball is kicked into the air. its height above the ground can be approximated
by using the equation h = -3t2 + 15t, where h is the height above the ground in
meters and t is the time in seconds.
a) what are the zeros of this relation?
b) when does the ball hit the ground?
c) when does the ball reach its maximum height?
d) what is the maximum height of the ball?

See below in bold.

Step-by-step explanation:

a)  h = -3t^2 + 15t = 0

-3t(t - 5) = 0

t = 0, 5 are the zeroes of the relation.

b)  The ball hits the ground when h = 0 so it is after 5 seconds.

c)  The path of the ball is a parabola which opens downwards so the maximum height  is when x = 5/2 = at 2.5 seconds.

d) this maximum height is -3(2.5)^2 + 15(2.5) = 18.75 meters.

im not sure

step-by-step explanation:

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)