Find the discriminant of the quadratic equation x2 + 6x + 14 = 0 and use it to determine the number and types of solutions.
b2 − 4ac
a.)−20; two nonreal solutions
b.)−20; one real solution
c.)92; two real solutions
d.)92; one real solution

The correct option is A) −20; Two non-real solutions

Step-by-step explanation:

Consider the provided equation.

Now compare the provided equation with the standard form of quadratic equation:

The discriminant of the quadratic equation can be calculated as:

If , then the equation has two non-real solutions.

If , then the equation has one real solutions.

If , then the equation has two real solutions.

Now by the comparison of the provided equation with the standard from, it can be concluded that a = 1, b = 6 and c = 14.

Substitute the respective values in the discriminant formula:

The value of D is -20 which is less than 0 thus the equation has two non real solutions.

Hence, the correct option is A) −20; Two non-real solutions

c. (3,2,6) is the answer.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer