Can someone with these 2 word problems asap.
4. a jet plane travels 2 times the speed of a commercial airplane. the distance between vancouver
and regina is 1730 km. if the flight from vancouver to regina on a commercial airplane takes
140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route?
5. a man goes fishing in a river and wants to know how long it will take him to get 10km upstream
to his favourite fishing location. the speed of the current is 3 km/hr and it takes his boat twice
as long to go 3km upstream as is does to go 4km downstream. how long will it take his boat to get to his fishing spot?

4.     4.66hours

5.  time_trip = 2.777 h

Step-by-step explanation:

4. A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouver and Regina is 1730 km. If the flight from Vancouver to Regina on a commercial airplane takes 140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route?

We know that

Speed_commercial = distance/ time_comm

Speed_commercial = 1730 km/ time_comm

Then,

Speed_jet = distance/ time_jet = 2*Speed_commercial

Speed_jet =   1730 km/ time_jet = 2*Speed_commercial

time_comm = 2.333 h + time_jet

1730 km/ time_jet = 2*1730 km/ time_comm

time_comm = 2*time_jet

time_comm = 2*(time_comm  - 2.333h)

time_comm = (2*time_comm  - 4.666h)

time_comm  = 4.666 h

5. A man goes fishing in a river and wants to know how long it will take him to get 10km upstream to his favourite fishing location. The speed of the current is 3 km/hr and it takes his boat twice as long to go 3km upstream as is does to go 4km downstream. How long will it take his boat to get to his fishing spot?

Distance = 10 km upstream

Speed_current = 3 km/h

Upstream

(Speed_boat - Speed_current)  = 3 km / (2*time_downstream)

Downstream

(Speed_boat + Speed_current)  = 4 km / (time_downstream)

We subtract both equations

(Speed_boat + Speed_current) - (Speed_boat - Speed_current) = 4 km / (time_downstream) - 3 km / (2*time_downstream)

2*Speed_current = (5/2 km)/ time_downstream

2*(3 km/h)= (5/2 km)/ time_downstream

time_downstream = 0.416 h

(Speed_boat + 3km/h)  = 4 km / (0.416 h)

Speed_boat  = 6.6 km/h

Trip upstream

(Speed_boat - Speed_current)  = 10 km / (time_trip)

time_trip = 10 km/(3.6 km/h) = 2.777 h

time_trip = 2.777 h

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

replication and blocking

step-by-step explanation: