The below shows a square abcd and an equilateral triangle dpc:
nick makes the chart shown below to prove that triangle apd is congruent to triangle bpc:
which of the following completes nick's proof?
a) p is the vertex of the equilateral triangle
b) sides of equilateral triangle dpc are equal
c) triangle apb is an isosceles triangle
d) dc is the base of an equilateral triangle

Option B)  Sides of equilateral triangle DPC are equal

Step-by-step explanation:

As given:

DPC is an equilateral triangle

By definition of equilateral triangles: All the three sides of triangle DPC will be equal in length to each other

i.e.

DP=PC=DC

In Nick's proof , justification of DP=PC is option B) Sides of equilateral triangle DPC are equal !

B- Sides of equilateral triangle DPC are equal

Step-by-step explanation:

I took the test and it was correct

entering that problem on the tube might get you an answer

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl