What is the square footage for this property described by the metes-and-bounds method? beginning at the point of the southerly side of smith street, 200 feet easterly from the corner formed by the intersection of the southerly side of smith street and the easterly side of johnson street; then east 200 feet; then south 100 feet; then west 200 feet; then north 100 feet to the pob.
a. 20,000 square feetb. 10,000 square feetc. 5,000 square feetd. 15,000 square feet

The correct option is option A.

The area of a rectangle is the region covered by the rectangle in a two-dimensional plane.

The formula to finding the area of the rectangle is,

It is given that,

Length=100 ft

Breadth=200 ft

Now, substituting the given values into the above formula we get,

The required area is 20,000 square feet.

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  A.  20,000 square feet

Step-by-step explanation:

The description is that of a rectangle 200 ft long and 100 ft wide. The area is the product of those dimensions:

  area = (200 ft)(100 ft) = 20,000 ft²

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.