If you apply the changes below to the quadratic parent function, f(x)=x^2, what is the equation of the new function? shifted 1 unit right. vertically streched by a factor of 5. reflected over the x-axis.

Step-by-step explanation:

The given parent function is:

If we shift to the right by 1 unit, the function becomes:

If we stretch by a factor of 5, the function becomes,

Finally reflecting over the x-axis gives:

f'''(x)=-5(x-1)^2

Step-by-step explanation:

Given:

f(x)= x^2

Shifting 1 unit to right means subtracting 1 from the function i.e

f(x-1)=(x-1)^2

f'(x)=(x-1)^2

now vertically stretching above f'(x)  by a factor of 5:

5f'(x)=5(x-1)^2

f''(x)=5(x-1)^2

finally reflecting above f'''(x) over the x-axis:

-f''(x)=-5(x-1)^2

f'''(x)=-5(x-1)^2 !

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb