F(x) = -x^3 + 3x^2 + x - 3 using the end behavior of f(x), determine the graph of the function

Here, the given function,

Since, the leading coefficient is negative, and degree is odd,

Thus, the end behaviour of the function is,

Therefore, the graph rises to the left and falls to the right.

Now, when f(x) = 0

That is, graph intercepts the x-axis at (3, 0), (1, 0) and (-1, 0).

When x = 0,

That is, graph intersects the y-axis at ( 0, -3),

Also, for 0 > x > -1 , f(x) is decreasing,

For 2.55 > x > 0, f(x) is increasing,

For 3 > x > 2.55, f(x) is decreasing,

Hence, by the above explanation we can plot the graph of the function ( shown below )

4th option is correct xy=-10

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