Forty ounces of lazy lawn fertilizer covers 1,250 square feet of lawn.
(a) how many ounces would be required to cover a 6,000 square foot lawn?
(b) if lazy lawn costs $1.17 for a 24 ounce bag, what is the total cost (in dollars) to fertilize the lawn?
$

192 oz needed at a cost of $9.36

Step-by-step explanation:

Set these up as proportions.  The first set of ratios will have the number of ounces on the top and the square feet on the bottom:

If we are looking for the number of ounces it will take to cover 6000 square feet, then the unknown x is on top with ounces and the 6000 goes on bottom with the square feet:

Cross multiply to get

1250x = 240000 so

x = 192 ounces

That is how many ounces of fertilizer it takes to cover the lawn.  Now you want to know what it will cost for 192 ounces of fertilizer.  So use a proportion again with cost on top and ounces on bottom:

Cross multiply to get

24x = 224.64 so

x = $9.36

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

1.3 million hoops i believe