Kevin asked some of his friends how many hours they had worked during the previous week at their after-school jobs. the results are shown below.
6 5 6 3 6 6 9 8 6 3 8 5
5 8 6 5 8 6 5 8 5 8 8 3
construct a frequency distribution table for the data given using a class width of 1 and starting with the class 0–0.9. what is the frequency of the class 3–3.9?
0
2
1
3

D. 3

Step-by-step explanation:

For the frequency distribution table you will have your table as below;

class width = 1

starting class= 0-0.9

class      tally              frequency

0-0.9         -                  0

1-1.9           -                  0

2-2.9          -                 0

3-3.9          III               3

4-4.9           -                 0

5-5.9         I              6

6-6.9       II                7

7-7.9        -                     0

8-8.9         II               7

9-9.9            I                 1

Total                           24

The class 3-3.9 has a frequency of 3

1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)