Suppose that a company claims that its coffee cans contain 6.8 ounces of
coffee, on average. you take many large samples, and find, each time, that the
mean weight of the sample is within the 95% confidence interval. which of
the following would be a reasonable conclusion?
o
a. the company's coffee cans do not contain 6.8 ounces of coffee,
on average.
o
b. the company's coffee cans contain 6.8 ounces of coffee, on
average.
c. the company's coffee cans contain more than 6.8 ounces of
coffee, on average.
d. the company's coffee cans contain less than 6.8 ounces of
coffee, on average

linearly: 8560 bacteria

exponentially: approximately 75233 bacteria

step-by-step explanation:

assuming it is not exponential (we would have some really complicated logarithms), let's say it is linear. then, after 5 hours, it increased by 1200 bacteria, so every hour it increases by 240 bacteria. this means that after 19 hours, we get 19 * 240 + 4000 bacteria or 3800 + 760 + 4000 = 7800 + 760 = 8560 bacteria.

because it says round your answer, i will do this exponentially (with a calculator, of course). first, we need to find how much it multiplies by every hour, by taking the 5th root of 52/40 or 13/10. this is approximately 0.167. we still need to add 1 to this, because we are multiplying by that number, not adding that amount of the number. now, we just calculate 4000 * (1.167)^19. use a calculator to get approximately 75232.6, or 75233.

the answer is b.

64

step-by-step explanation:

c=2πr=2·π·8≈64

cause it equals more