Two trains leave towns 1152km apart at the same time and travel toward each other. one train travels 14km/h slower than the other. if they meet in 4 hours, what is the rate of each train?

137 km/h and 151 km/h

Step-by-step explanation:

Let x km/h be the rate of slower train, then (x+14) km/h is the rate of faster train.

In 4 hours:

Since they meet in 4 hours, then they cover in total the whole distance between two cities, so

4x+4(x+14)=1152

Solve this equation for x:

4x+4x+56-1152

8x=1152-56

8x=1096

x=1096/8

x=137 km/h

x+14=137+14=151 km/h

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.