What is the value of 4a^3–2b^2+5 when a = 3 and b =–2

105

Step-by-step explanation:

Evaluate 4 a^3 - 2 b^2 + 5 where a = 3 and b = -2:

4 a^3 - 2 b^2 + 5 = 4×3^3 - 2×(-2)^2 + 5

3^3 = 3×3^2:

4×3×3^2 - 2×(-2)^2 + 5

3^2 = 9:

4×3×9 - 2×(-2)^2 + 5

3×9 = 27:

4×27 - 2×(-2)^2 + 5

(-2)^2 = 4:

4×27 - 24 + 5

4×27 = 108:

108 - 2×4 + 5

-2×4 = -8:

108 + -8 + 5

| | 1 |  

| 1 | 0 | 8

+ | | | 5

| 1 | 1 | 3:

113 - 8

| | 0 | 13

| 1 | 1 | 3

- | | | 8

| 1 | 0 | 5:

 105

105

Step-by-step explanation:

4a^3 -2b^2 +5

Let a=3 and b= -2

4 (3)^3 -2 (-2)^2 +5

4 *27 -2 (4) +5

108 -8+5

105

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: