Ajet plane travels 2 times the speed of a commercial airplane. the distance between vancouver
and regina is 1730 km. if the flight from vancouver to regina on a commercial airplane takes
140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route? ( show steps: ))

The time of a commercial airplane is 280 minutes

Step-by-step explanation:

Let

x > the speed of a commercial airplane

y > the speed of a jet plane

t > the time that a jet airplane takes  from Vancouver to Regina

we know that

The speed is equal to divide the distance by the time

y=2x > equation A

The speed of a commercial airplane is equal to

x=1,730/(t+140) > equation B

The speed of a jet airplane is equal to

y=1,730/t > equation C

substitute equation B and equation C in equation A

1,730/t=2(1,730/(t+140))

Solve for t

1/t=(2/(t+140))

t+140=2t

2t-t=140

t=140 minutes

The time of a commercial airplane is

t+140=140+140=280 minutes

step by step solution :

step   1   :

1.1     4 = 22

(4)3 = (22)3 = 26

equation at the end of step   1   :

  ((23) • 26)2

step   2   :

equation at the end of step   2   :

  (23 • 26)2

step   3   :

final result :

  218

ya

i think the answer is c sorry if it's wrong