Solve sin θ+1= cos2θ on the interval 0≤ θ< 2 pi.
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Step-by-step explanation:

Applying double angle identity:

Doing so would give:

We need to get everything to one side so we have 0 on one side.

Subtract 1 on both sides:

Add on both sides:

Let's factor the left-hand side.

The two terms on the left-hand side have a common factor of .

.

This implies we have:

.

We need to solve both equations.

You are asking they be solved in the interval .

This means look at your unit circle and find when you have your y-coordinates is 0.

You this at 0 and . (I didn't include because you don't have a equal sign at the endpoint of .

Now let's solve

Subtract 1 on both sides:

Divide both sides by 2:

Now we are going to go and look for when the y-coordinates are -1/2.

This happens at and .

The solution set given the restrictions is

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: