Elly has 2 rectangular gardens. one measures 1809 cm by 2891 cm and the other measures 738 cm by 249 cm. elly wants to put a fence around both, how much does she need to buy?

She needs 11374 cm to buy

Step-by-step explanation:

* Lets explain how to solve the problem

- The dimensions of the first rectangle is 1809 cm and 2891 cm

- The dimensions of the first rectangle is 738 cm and 249 cm

- Elly wants to put a fence around both

- To find the length of the fence calculate the perimeters of the two

 rectangles

- The perimeter of the rectangle = 2(b + h), where b , h are the

 dimensions of the rectangle

# First rectangle

∵ The dimensions are 1809 cm and 2891 cm

∵ P = 2(b + h)

∴ P = 2(1809 + 2891) = 2(4700) = 9400 cm

# Second rectangle

∵ The dimensions are 738 cm and 249 cm

∵ P = 2(b + h)

∴ P = 2(738 + 249) = 2(987) = 1974 cm

∵ The length of the fence = the sum of the perimeters of the two

  rectangles

∴ The length of the fence = 9400 + 1974 = 11374 cm

* She needs 11374 cm to buy

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!