From a group of 8 volunteers, including andrew and karen, 4 people are to be selected at random to organize a charity event. what is the probability that andrew will be among the 4 volunteers selected and karen will not?

The probability that Andrew will be among the 4 volunteers selected and Karen will not is 2/7.

Step-by-step explanation:

From the given information it is clear that

The total number of volunteers, including Andrew and Karen = 8

The total number of volunteers, excluding Andrew and Karen = 8-2 = 6

We need to find the probability that Andrew will be among the 4 volunteers selected and Karen will not.

Total number of ways of selecting r volunteers from n volunteers is

Total number of ways of selecting 4 volunteers from 8 volunteers is

Total number of ways of selecting 4 volunteers from 8 volunteers, so that Andrew will be among the 4 volunteers selected and Karen will not is

The probability that Andrew will be among the 4 volunteers selected and Karen will not is

Therefore the probability that Andrew will be among the 4 volunteers selected and Karen will not is 2/7.

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

i dont know

step-by-step explanation: