Dwayne is selling hamburgers and cheeseburgers. he has 100 burger buns. each hamburger sells for $3, and each cheeseburger sells for $3.50. which system of inequalities represents the number of hamburgers, h, and the number of cheeseburgers, c, he must sell to have sales of at least $80?

In this question, we know that:

With the information above, we can make our inequalities.

The letter "h" would be representing hamburgers in this case. Since each hamburger cost $3, we would put it as 3h.

The letter "c" would be representing cheeseburgers. Since each cheeseburger cost $3.50, we would put it as 3.5c.

He needs to at least $80, meaning that he needs to make $80 or more.

So when we put those together, the inequality should be:

We're not done yet, we also have another inequality to make.

We know that he has 100 hamburger buns, but we don't know how many hamburgers or cheeseburgers he sold. We would represent is as "less than or equal to" because we can't get any higher than 100.

So this would be represented as:

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.