Mathematics
Mathematics, 20.07.2019 03:20, emilygoolsby2123

Solve for x: 2 over 10 equals 3 over quantity x minus 9

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Mathematics, 24.06.2019 01:30, saintsfan2004
Quadrilateral pqrs is located at p (0, 1), q (3, 2), r (4, 0), and s (1, βˆ’1). russell and jamie have both classified pqrs differently. examine their proofs. who is correct? russell pqrs is a parallelogram because opposite sides are both congruent and parallel. segment pq p (0, 1) and q (3, 2) d equals the square root of the quantity 3 minus 0 all squared plus 2 minus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10 m equals 2 minus 1 over 3 minus 0 equals one third segment sr s (1, βˆ’1) and r (4, 0) d equals the square root of the quantity 4 minus 1 all squared plus 0 plus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10 m equals 0 plus 1 over 4 minus 1 equals one third segment ps p (0, 1) and s (1, βˆ’1) d equals the square root of the quantity 1 minus 0 all squared plus negative 1 minus 1 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5 m equals negative 1 minus 1 over 1 minus 0 equals negative 2 over 1 segment qr q (3, 2) and r (4, 0) d equals the square root of the quantity 4 minus 3 all squared plus 0 minus 2 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5 m equals 0 minus 2 over 4 minus 3 equals negative 2 over 1 segments pq and sr are both congruent and parallel, and segments ps and qr are both congruent and parallel. pqrs is a rectangle because opposite sides are both congruent and parallel and adjacent sides are perpendicular. jamie segment pq p (0, 1) and q (3, 2) d equals the square root of the quantity 3 minus 0 all squared plus 2 minus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10 m equals 2 minus 1 over 3 minus 0 equals one third segment sr s (1, βˆ’1) and r (4, 0) d equals the square root of the quantity 4 minus 1 all squared plus 0 plus 1 all squared equals the square root of the quantity 9 plus 1 equals the square root of 10m equals 0 plus 1 over 4 minus 1 equals one third segment ps p (0, 1) and s (1, βˆ’1) d equals the square root of the quantity 1 minus 0 all squared plus negative 1 minus 1 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5 m equals negative 1 minus 1 over 1 minus 0 equals negative 2 over 1 segment qr q (3, 2) and r (4, 0) d equals the square root of the quantity 4 minus 3 all squared plus 0 minus 2 all squared equals the square root of the quantity 1 plus 4 equals the square root of 5 m equals 0 minus 2 over 4 minus 3 equals negative 2 over 1 segments pq and sr are both congruent and parallel, and segments ps and qr are both congruent and parallel. segments ps and sr are perpendicular. segments pq and qr are perpendicular.
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Mathematics, 11.07.2019 02:30, 2021andrewkell
Question 1 solve for x using the quadratic formula: x2 βˆ’ 6x + 9 = 0 x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x = 6 x = 3 x = 1 x = 0 question 2 solve: 49x2 βˆ’ 60 = 0 round your answer to the nearest hundredth. x = 0 x = βˆ’3.32 and x = 3.32 x = βˆ’1.11 and x = 1.11 x = βˆ’0.82 and x = 0.82 question 3 when the solution of x2 βˆ’ 9x βˆ’ 6 is expressed as 9 plus or minus the square root of r, all over 2, what is the value of r? x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a 6 42 57 105 question 4 identifying the values a, b, and c is the first step in using the quadratic formula to find solution(s) to a quadratic equation. what are the values a, b, and c in the following quadratic equation? βˆ’6x2 = βˆ’9x + 7 a = 9, b = 7, c = 6 a = βˆ’9, b = 7, c = βˆ’6 a = βˆ’6, b = 9, c = βˆ’7 a = βˆ’6, b = βˆ’9, c = 7 question 5 use the quadratic formula to find the exact solutions of x2 βˆ’ 5x βˆ’ 2 = 0. x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x equals 5 plus or minus the square root of 33, all over 2 x equals negative 5 plus or minus the square root of 33, all over 2 x equals 5 plus or minus the square root of 17, all over 2 x equals negative 5 plus or minus the square root of 17, all over 2 question 6 a portion of the quadratic formula proof is shown. fill in the missing statement. statements reasons x squared plus b over a times x plus the quantity b over 2 times a squared equals negative 4 times a times c all over 4 times a squared plus b squared over 4 a squared find a common denominator on the right side of the equation x squared plus b over a times x plus the quantity b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared add the fractions together on the right side of the equation the quantity x plus b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared rewrite the perfect square trinomial on the left side of the equation as a binomial squared x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 4 times a squared take the square root of both sides of the equation x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a simplify the right side of the equation ? subtract the quantity b over 2 times a from both sides of the equation x equals b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over a x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x plus b over 2 times a equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a question 7 the quadratic equation 3x2 + 45x + 24 = 0 was solved using the quadratic formula, x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a. one solution is βˆ’14.45. what is the other solution? round to the hundredths place. βˆ’1.11 βˆ’0.55 0.52 14.45 question 8 the quadratic formula, x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a, was used to solve the equation. 2x2 βˆ’ 8x + 7 = 0. fill in the missing denominator of the solution. 4 plus or minus the square root of 2, all over blank βˆ’16 2 4 14 question 9 identifying the values a, b, and c is the first step in using the quadratic formula to find solution(s) to a quadratic equation. what are the values a, b, and c in the following quadratic equation? βˆ’6x2 βˆ’ 8x + 12 a = βˆ’6, b = βˆ’8, c = 12 a = 6, b = 8, c = 12 a = 8, b = 12, c = 0 a = βˆ’8, b = 12, c = 0
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Solve for x: 2 over 10 equals 3 over quantity x minus 9...

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