which is the equation of an ellipse with directrices at y = ±2 and foci at (0, 1) and (0, −1)?
x squared over 4 plus y squared over 1 equals 1
x squared over 2 plus y squared over 1 equals 1
x squared over 1 minus y squared over 4 equals 1
x squared over 1 minus y squared over 2 equals 1

Step-by-step explanation:

It was given that, the ellipse has directrices at

The directrices has equation: , where is the eccentricity of the ellipse.

eqn(1)

The foci are at: (0,1) qnd (0,-1)

Also, the foci are given by:

eqn(2)

Solving equation (1) and (2) simultaneously we get;

and

We use the relation, to get:

.

The equation of the ellipse is given by:

We substitute the values to get:

Or

ian gonna lie that is way to much

answer:   y=2x-3

step-by-step explanation: