which is the equation of a hyperbola with directrices at x = ±3 and foci at (4, 0) and (−4, 0)?
x squared over 16 minus y squared over 4 equals 1
x squared over 12 minus y squared over 4 equals 1
y squared over 16 minus x squared over 4 equals 1
y squared over 12 minus x squared over 4 equals 1

x+y=90

x=30-y=x

step-by-step explanation:

if you understand you will get the answer

10010010001010010101001001010010100101010010101010010010101010110010001011010010010001

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.