Arectangle is 9 ft long and 40 in. wide. what is its
area in square feet?

29.97 square feet

Step-by-step explanation:

Given

The length of rectangle = 9 ft

The width of rectangle = 40 in

We have to bring the length and width in same unit. As the area is required in square feet so we will convert width in feet

The width will be divided by 12 to be onverted into feet

So,

Width = 40/12 = 3.33 feet

Now

Area = Length * width

= 9 * 3.33

= 29.97 square feet ..

Area of rectangle = 30 square feet

Step-by-step explanation:

We are given that a rectangle is 9 feet long and 40 inches wide and we are to find its area in square feet.

For this, we will covert the width of the rectangle to feet and then find the area.

We know that:

So width in feet is 3.3 feet.

Area of rectangle = = 30 square feet

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

answer: i think one of the answer is $150 and $300?

step-by-step explanation: