Ametallurgist has an alloy with 16% titanium and an alloy with 30% titanium. he needs 100 grams of an alloy with 23% titanium. how much of each alloy should be mixed to attain the 100 grams of alloy with 23% titanium?
nothing grams of the alloy with 16% of titanium are needed.

Let x = amount of 16% alloy, and y = amount of 30% alloy he should use.

Mixing the alloys will result in a compound weighing x + y = 100 grams.

For each gram of the 16% alloy used, 0.16 gram of titanium is contributed; similarly, for each gram of the 30% alloy used, there's a contribution of 0.3 gram. He wants to end up with an alloy of 23% titanium, or 23 grams (23% of 100), so that 0.16x + 0.3y = 23.

Solve the system:

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

i don't have the answer rn but go to math papa. it shows the steps and the answer. hope this : )

step-by-step explanation: