When the positive integer "n" is divided by 3, the remainder is 2 and when "n" is divided by 5, the remainder is 1. what is the least possible value of "n" i really need this done out step by step and explained in detail. im not grasping

The number would be 11.

Step-by-step explanation:

Dividend = Divisor × Quotient + Remainder

Given,

"n" is divided by 3, the remainder is 2,

So, the number = 3n + 2,

"n" is divided by 5, the remainder is 1,

So, the number = 5n + 1

Thus, we can write,

3n + 2 = 5n + 1

-2n = -1

n = 0.5,

Therefore, number must be the multiple of 0.5 but is not divided by 3 or 5,

Possible numbers = { 1, 2, 4, 7, 8, 11 }

Since, 1 and 4 do not give the remainder 2 after divided by 3,

And, 2, 7 and 8 do not give the remainder 1 after divided by 5,

Hence, the least positive integer number that gives remainder 2 and 1 after divided by 3 and 5 respectively is 11.

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!