Use the given data to find the 95% confidence interval estimate of the population mean μ. assume that the population has a normal distribution. iq scores of professional athletes: sample size n=10 mean x¯=104 standard deviation s=10

For 95% Confidence Interval:

Upper Limit = 110.2

Lower Limit = 97.8

95% Confidence Interval = [97.8, 110.2]

Step-by-step explanation:

Given that,

Mean(M) = 104

Standard Deviation(SD) = 10

Sample Size(n) = 10

Formula for calculating 95% Confidence Interval are as follows:

Standard error(SE) =

                         =

                         = 3.164

⇒ M ± × SE

= 104 ± (1.96)(3.164)

= 104 ± 6.20

∴ Upper Limit = 104 + 6.20 = 110.2

   Lower Limit = 104 - 6.20 = 97.8

So,

95% Confidence Interval = [97.8, 110.2]

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

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step-by-step explanation: