The median is the same as the
a. second quartile
b. mode
c. mean
d. interquartile range

Option A

The median is the same as the _ Second quartile_.

Step-by-step explanation:

Given a series of data ordered from least to greatest, the median is the value that is in the center.

That is, the median represents the value that divides 50% of the data.

In the same way, the first quartile is the value that divides 25% of the data and the third quartile is the value that divides 75% of the data.

The second quartile is the number that divides 50% of the data.

Then notice that the second quartile is equal to the median

Then te answer is the option A.

A. Second quartile

Step-by-step explanation:

Median is the middle value of the data when arranged, it divides the data in two halves.

Also second quartile is the point in data that divides the data into two quarters.

Hence second quartile is median of data!

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.